x^2-16x-3x=180

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Solution for x^2-16x-3x=180 equation:



x^2-16x-3x=180
We move all terms to the left:
x^2-16x-3x-(180)=0
We add all the numbers together, and all the variables
x^2-19x-180=0
a = 1; b = -19; c = -180;
Δ = b2-4ac
Δ = -192-4·1·(-180)
Δ = 1081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{1081}}{2*1}=\frac{19-\sqrt{1081}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{1081}}{2*1}=\frac{19+\sqrt{1081}}{2} $

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